Integrand size = 20, antiderivative size = 131 \[ \int x^2 \sqrt {c x^2} (a+b x)^n \, dx=-\frac {a^3 \sqrt {c x^2} (a+b x)^{1+n}}{b^4 (1+n) x}+\frac {3 a^2 \sqrt {c x^2} (a+b x)^{2+n}}{b^4 (2+n) x}-\frac {3 a \sqrt {c x^2} (a+b x)^{3+n}}{b^4 (3+n) x}+\frac {\sqrt {c x^2} (a+b x)^{4+n}}{b^4 (4+n) x} \]
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Time = 0.03 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {15, 45} \[ \int x^2 \sqrt {c x^2} (a+b x)^n \, dx=-\frac {a^3 \sqrt {c x^2} (a+b x)^{n+1}}{b^4 (n+1) x}+\frac {3 a^2 \sqrt {c x^2} (a+b x)^{n+2}}{b^4 (n+2) x}-\frac {3 a \sqrt {c x^2} (a+b x)^{n+3}}{b^4 (n+3) x}+\frac {\sqrt {c x^2} (a+b x)^{n+4}}{b^4 (n+4) x} \]
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Rule 15
Rule 45
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {c x^2} \int x^3 (a+b x)^n \, dx}{x} \\ & = \frac {\sqrt {c x^2} \int \left (-\frac {a^3 (a+b x)^n}{b^3}+\frac {3 a^2 (a+b x)^{1+n}}{b^3}-\frac {3 a (a+b x)^{2+n}}{b^3}+\frac {(a+b x)^{3+n}}{b^3}\right ) \, dx}{x} \\ & = -\frac {a^3 \sqrt {c x^2} (a+b x)^{1+n}}{b^4 (1+n) x}+\frac {3 a^2 \sqrt {c x^2} (a+b x)^{2+n}}{b^4 (2+n) x}-\frac {3 a \sqrt {c x^2} (a+b x)^{3+n}}{b^4 (3+n) x}+\frac {\sqrt {c x^2} (a+b x)^{4+n}}{b^4 (4+n) x} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 97, normalized size of antiderivative = 0.74 \[ \int x^2 \sqrt {c x^2} (a+b x)^n \, dx=\frac {c x (a+b x)^{1+n} \left (-6 a^3+6 a^2 b (1+n) x-3 a b^2 \left (2+3 n+n^2\right ) x^2+b^3 \left (6+11 n+6 n^2+n^3\right ) x^3\right )}{b^4 (1+n) (2+n) (3+n) (4+n) \sqrt {c x^2}} \]
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Time = 0.41 (sec) , antiderivative size = 136, normalized size of antiderivative = 1.04
method | result | size |
gosper | \(-\frac {\sqrt {c \,x^{2}}\, \left (b x +a \right )^{1+n} \left (-b^{3} n^{3} x^{3}-6 b^{3} n^{2} x^{3}+3 a \,b^{2} n^{2} x^{2}-11 b^{3} n \,x^{3}+9 a \,b^{2} n \,x^{2}-6 b^{3} x^{3}-6 a^{2} b n x +6 a \,b^{2} x^{2}-6 a^{2} b x +6 a^{3}\right )}{b^{4} x \left (n^{4}+10 n^{3}+35 n^{2}+50 n +24\right )}\) | \(136\) |
risch | \(-\frac {\sqrt {c \,x^{2}}\, \left (-b^{4} n^{3} x^{4}-a \,b^{3} n^{3} x^{3}-6 b^{4} n^{2} x^{4}-3 a \,b^{3} n^{2} x^{3}-11 b^{4} n \,x^{4}+3 a^{2} b^{2} n^{2} x^{2}-2 x^{3} a n \,b^{3}-6 b^{4} x^{4}+3 a^{2} n \,x^{2} b^{2}-6 x \,a^{3} n b +6 a^{4}\right ) \left (b x +a \right )^{n}}{x \left (3+n \right ) \left (4+n \right ) \left (2+n \right ) \left (1+n \right ) b^{4}}\) | \(156\) |
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Time = 0.24 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.17 \[ \int x^2 \sqrt {c x^2} (a+b x)^n \, dx=\frac {{\left (6 \, a^{3} b n x + {\left (b^{4} n^{3} + 6 \, b^{4} n^{2} + 11 \, b^{4} n + 6 \, b^{4}\right )} x^{4} - 6 \, a^{4} + {\left (a b^{3} n^{3} + 3 \, a b^{3} n^{2} + 2 \, a b^{3} n\right )} x^{3} - 3 \, {\left (a^{2} b^{2} n^{2} + a^{2} b^{2} n\right )} x^{2}\right )} \sqrt {c x^{2}} {\left (b x + a\right )}^{n}}{{\left (b^{4} n^{4} + 10 \, b^{4} n^{3} + 35 \, b^{4} n^{2} + 50 \, b^{4} n + 24 \, b^{4}\right )} x} \]
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\[ \int x^2 \sqrt {c x^2} (a+b x)^n \, dx=\begin {cases} \frac {a^{n} x^{3} \sqrt {c x^{2}}}{4} & \text {for}\: b = 0 \\\int \frac {x^{2} \sqrt {c x^{2}}}{\left (a + b x\right )^{4}}\, dx & \text {for}\: n = -4 \\\int \frac {x^{2} \sqrt {c x^{2}}}{\left (a + b x\right )^{3}}\, dx & \text {for}\: n = -3 \\\int \frac {x^{2} \sqrt {c x^{2}}}{\left (a + b x\right )^{2}}\, dx & \text {for}\: n = -2 \\\int \frac {x^{2} \sqrt {c x^{2}}}{a + b x}\, dx & \text {for}\: n = -1 \\- \frac {6 a^{4} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} + \frac {6 a^{3} b n x \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} - \frac {3 a^{2} b^{2} n^{2} x^{2} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} - \frac {3 a^{2} b^{2} n x^{2} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} + \frac {a b^{3} n^{3} x^{3} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} + \frac {3 a b^{3} n^{2} x^{3} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} + \frac {2 a b^{3} n x^{3} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} + \frac {b^{4} n^{3} x^{4} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} + \frac {6 b^{4} n^{2} x^{4} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} + \frac {11 b^{4} n x^{4} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} + \frac {6 b^{4} x^{4} \sqrt {c x^{2}} \left (a + b x\right )^{n}}{b^{4} n^{4} x + 10 b^{4} n^{3} x + 35 b^{4} n^{2} x + 50 b^{4} n x + 24 b^{4} x} & \text {otherwise} \end {cases} \]
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Time = 0.22 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.89 \[ \int x^2 \sqrt {c x^2} (a+b x)^n \, dx=\frac {{\left ({\left (n^{3} + 6 \, n^{2} + 11 \, n + 6\right )} b^{4} \sqrt {c} x^{4} + {\left (n^{3} + 3 \, n^{2} + 2 \, n\right )} a b^{3} \sqrt {c} x^{3} - 3 \, {\left (n^{2} + n\right )} a^{2} b^{2} \sqrt {c} x^{2} + 6 \, a^{3} b \sqrt {c} n x - 6 \, a^{4} \sqrt {c}\right )} {\left (b x + a\right )}^{n}}{{\left (n^{4} + 10 \, n^{3} + 35 \, n^{2} + 50 \, n + 24\right )} b^{4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 300 vs. \(2 (123) = 246\).
Time = 0.29 (sec) , antiderivative size = 300, normalized size of antiderivative = 2.29 \[ \int x^2 \sqrt {c x^2} (a+b x)^n \, dx={\left (\frac {6 \, a^{4} a^{n} \mathrm {sgn}\left (x\right )}{b^{4} n^{4} + 10 \, b^{4} n^{3} + 35 \, b^{4} n^{2} + 50 \, b^{4} n + 24 \, b^{4}} + \frac {{\left (b x + a\right )}^{n} b^{4} n^{3} x^{4} \mathrm {sgn}\left (x\right ) + {\left (b x + a\right )}^{n} a b^{3} n^{3} x^{3} \mathrm {sgn}\left (x\right ) + 6 \, {\left (b x + a\right )}^{n} b^{4} n^{2} x^{4} \mathrm {sgn}\left (x\right ) + 3 \, {\left (b x + a\right )}^{n} a b^{3} n^{2} x^{3} \mathrm {sgn}\left (x\right ) + 11 \, {\left (b x + a\right )}^{n} b^{4} n x^{4} \mathrm {sgn}\left (x\right ) - 3 \, {\left (b x + a\right )}^{n} a^{2} b^{2} n^{2} x^{2} \mathrm {sgn}\left (x\right ) + 2 \, {\left (b x + a\right )}^{n} a b^{3} n x^{3} \mathrm {sgn}\left (x\right ) + 6 \, {\left (b x + a\right )}^{n} b^{4} x^{4} \mathrm {sgn}\left (x\right ) - 3 \, {\left (b x + a\right )}^{n} a^{2} b^{2} n x^{2} \mathrm {sgn}\left (x\right ) + 6 \, {\left (b x + a\right )}^{n} a^{3} b n x \mathrm {sgn}\left (x\right ) - 6 \, {\left (b x + a\right )}^{n} a^{4} \mathrm {sgn}\left (x\right )}{b^{4} n^{4} + 10 \, b^{4} n^{3} + 35 \, b^{4} n^{2} + 50 \, b^{4} n + 24 \, b^{4}}\right )} \sqrt {c} \]
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Time = 0.37 (sec) , antiderivative size = 214, normalized size of antiderivative = 1.63 \[ \int x^2 \sqrt {c x^2} (a+b x)^n \, dx=\frac {{\left (a+b\,x\right )}^n\,\left (\frac {x^4\,\sqrt {c\,x^2}\,\left (n^3+6\,n^2+11\,n+6\right )}{n^4+10\,n^3+35\,n^2+50\,n+24}-\frac {6\,a^4\,\sqrt {c\,x^2}}{b^4\,\left (n^4+10\,n^3+35\,n^2+50\,n+24\right )}+\frac {6\,a^3\,n\,x\,\sqrt {c\,x^2}}{b^3\,\left (n^4+10\,n^3+35\,n^2+50\,n+24\right )}+\frac {a\,n\,x^3\,\sqrt {c\,x^2}\,\left (n^2+3\,n+2\right )}{b\,\left (n^4+10\,n^3+35\,n^2+50\,n+24\right )}-\frac {3\,a^2\,n\,x^2\,\sqrt {c\,x^2}\,\left (n+1\right )}{b^2\,\left (n^4+10\,n^3+35\,n^2+50\,n+24\right )}\right )}{x} \]
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